by BlastRoom
Calculate theoretical yield, actual yield, and percent yield in stoichiometry.
#chemistry

20 questions
One question set, multiple game modes. Tap any game to see it in action. Not sure which to pick?
Answer to place stones and capture territory.
Outrun the snow together.
Earn blasts, then hunt the other team.
Answer to earn energy, then climb.

The class blasts through walls together.
Bid on mystery lots. Most money wins.
Sell tours. Nice, standard, or a total scam.
Answer, restock, and serve the rush.
More correct answers pulls the rope your way.
Answer, then shoot down the alien wave.
Answer, then tap to leap the frozen ridge.
A reaction has a theoretical yield of 20.0 g of product, but the lab produces 18.0 g. What is the percent yield?
A student calculates that 48.0 g of precipitate should form and collects 36.0 g. Which percent yield matches the data?
The theoretical yield of CO2 is 15.0 g, and the actual yield is 12.3 g. What is the percent yield?
A reaction should make 5.60 g of product, but 4.48 g is recovered. What percent yield should be reported?
A synthesis of AlCl3 has a theoretical yield of 6.80 g and an actual yield of 5.78 g. What is the percent yield?
A student expects 125 g of product but isolates 98.5 g after filtration and drying. What is the percent yield?
A reaction's theoretical yield is 0.640 mol, but the measured actual yield is 0.704 mol. What percent yield results?
A reaction has a theoretical yield of 40.0 g and a percent yield of 75.0%. What actual yield was collected?
If the theoretical yield is 18.0 g and the percent yield is 66.7%, what actual yield should be recorded?
A gas-forming reaction has a theoretical yield of 0.500 mol product and a percent yield of 92.0%. How much product actually formed?
A lab report lists a theoretical yield of 125 g and a percent yield of 84.0%. What was the actual yield?
CaCO3 → CaO + CO2. A student heats 10.0 g CaCO3 and collects 5.00 g CaO. Use CaCO3 = 100.09 g/mol and CaO = 56.08 g/mol. What is the percent yield?
For 2Mg + O2 → 2MgO, 6.00 g Mg reacts with excess O2 and 9.20 g MgO is collected. Use Mg = 24.31 g/mol and MgO = 40.31 g/mol. What is the percent yield?
N2 + 3H2 → 2NH3. From 7.00 g N2 with excess H2, a student gets 6.80 g NH3. Use N2 = 28.02 g/mol and NH3 = 17.03 g/mol. What is the percent yield?
2KClO3 → 2KCl + 3O2. Decomposing 12.3 g KClO3 gives 4.20 g O2. Use KClO3 = 122.55 g/mol and O2 = 32.00 g/mol. What is the percent yield?
Fe2O3 + 3CO → 2Fe + 3CO2. From 25.0 g Fe2O3, 16.5 g Fe is produced. Use Fe2O3 = 159.69 g/mol and Fe = 55.85 g/mol. What is the percent yield?
A student calculates a theoretical yield of 12.0 g but records an actual yield of 14.0 g. Which explanation best fits the percent yield?
Lab notes say stoichiometry predicts 8.40 g Cu, and the balance shows 7.65 g Cu after drying. Which statement identifies the yields correctly?
Which statement correctly compares theoretical yield and actual yield in a percent-yield problem?
A student spills some dry product before weighing it. What happens to the yields used in the percent-yield calculation?
Crack the passcode before the zombies get in.
Answer, then swat bugs for bonus points.
Race through questions at your own speed.
Same question on every screen. Fastest wins.

Pick a tile, answer, hit bonuses and steals.
Stoichiometry Word Problems
18 questions