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by BlastRoom
Rationalizing a complex denominator with the conjugate.
#algebra_2
40 questions
One question set, multiple game modes. Tap any game to see it in action. Not sure which to pick?
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Write (-4 - 7i)/(2 - 5i) in a + bi form.
Write (-6 + 6i)/(4i) in a + bi form.
What is the first step in writing (-4 + 6i)/(6 - 4i) in a + bi form?
Writing (2 + 4i)/(3 + i) in a + bi form, a student multiplied by 3 - i over itself but treated as 1 in the numerator, getting 1/5 + i. What is the correct answer?
What is the first step in writing (-7 - 4i)/(5 - 2i) in a + bi form?
Writing (3 + i)/(2 + 2i) in a + bi form, a student multiplied by 2 - 2i over itself but treated as 1 in the numerator, getting 1/2 - (1/2)i. What is the correct answer?
Write (2 - 5i)/(2i) in a + bi form.
Write (7 - 4i)/(5i) in a + bi form.
Write (-2 + 7i)/(5 + 2i) in a + bi form.
Write 8/(1 - 4i) in a + bi form.
Write (-2 - 5i)/(3 - 5i) in a + bi form.
Write (7 + 2i)/(5i) in a + bi form.
Writing (4 + 3i)/(1 - 3i) in a + bi form, a student multiplied by 1 + 3i over itself but treated as 1 in the numerator, getting 13/10 + (3/2)i. What is the correct answer?
Write (7 + 2i)/(1 - 5i) in a + bi form.
Write (-2 - 5i)/(1 - 3i) in a + bi form.
Write 12/(1 - 2i) in a + bi form.
Writing (6 + i)/(1 - i) in a + bi form, a student multiplied by 1 + i over itself but treated as 1 in the numerator, getting 7/2 + (7/2)i. What is the correct answer?
Write (6 - 2i)/(5 + 4i) in a + bi form.
Write (-6 - 3i)/(3i) in a + bi form.
Write 10/(3 - 2i) in a + bi form.
Write (-2 + 6i)/(-2i) in a + bi form.
What is the first step in writing (2 - 4i)/(3 - 4i) in a + bi form?
What is the first step in writing (2 - 2i)/(1 - 3i) in a + bi form?
Write (-4 - 3i)/(1 + 2i) in a + bi form.
What is the first step in writing (4 + 5i)/(6 + 3i) in a + bi form?
Write (5 + 6i)/(3 + 4i) in a + bi form.
Write (-6 + 4i)/(1 - 5i) in a + bi form.
Write (-4 + 7i)/(1 + 2i) in a + bi form.
Write (6 + 5i)/(2 + 4i) in a + bi form.
Write (4 - 3i)/(5 - 3i) in a + bi form.
Write (5 - 7i)/(3 + 2i) in a + bi form.
Writing (6 + 3i)/(1 - 2i) in a + bi form, a student multiplied by 1 + 2i over itself but treated as 1 in the numerator, getting 12/5 + 3i. What is the correct answer?
What is the first step in writing (-6 + 3i)/(3 + 2i) in a + bi form?
What is the first step in writing (4 - 7i)/(3 - 4i) in a + bi form?
Write (-4 + 2i)/(3i) in a + bi form.
What is the first step in writing (-2 + 5i)/(5 + 3i) in a + bi form?
Write (-4 + 6i)/(1 + 2i) in a + bi form.
Writing (5 + 3i)/(1 - 2i) in a + bi form, a student multiplied by 1 + 2i over itself but treated as 1 in the numerator, getting 11/5 + (13/5)i. What is the correct answer?
Write (-7 + 5i)/(-2i) in a + bi form.
Write 10/(3 - 4i) in a + bi form.
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Writing a Quadratic from Its Roots
20 questions
