A random sample of 400 airline passengers found 240 checked a bag. For $p$, the population proportion who check a bag, what are $\hat{p}$ and standard error, to three decimals?

In a random sample of 300 clinic patients, 72 used the online portal. For $p$, the population proportion who use the portal, find $\hat{p}$ and standard error, to three decimals.

A random sample of 625 seniors found 425 plan to attend college. For $p$, the population proportion of seniors who plan to attend college, what are $\hat{p}$ and standard error, to three decimals?

A random sample of 150 factory parts found 54 failed inspection. For $p$, the population proportion of parts that fail, find $\hat{p}$ and standard error, to three decimals.

A random sample of 500 county voters found 150 voted early. Using $z^{\ast }=1.645$ for a 90 percent confidence interval for $p$, the county proportion who voted early, what is the interval, to three decimals?

In a random sample of 800 city households, 520 recycle weekly. Using $z^{\ast }=1.96$ for a 95 percent interval for $p$, the city proportion that recycle weekly, compute the interval to three decimals.

A survey of 200 students found 84 ride the bus. With $z^{\ast }=1.645$ for a 90 percent confidence interval for $p$, the school proportion who ride the bus, what interval results, to three decimals?

A random sample of 1200 app users found 660 enabled alerts. Using $z^{\ast }=2.576$ for a 99 percent interval for $p$, the user proportion who enabled alerts, compute the interval to three decimals.

From 350 randomly sampled park visitors, 98 bought a day pass online. With $z^{\ast }=1.96$ for a 95 percent interval for $p$, the visitor proportion who buy online, what is the interval, to three decimals?

A random sample of 1000 cafeteria customers found 735 chose a vegetarian item. Using $z^{\ast }=2.326$ for a 98 percent interval for $p$, the customer proportion choosing vegetarian, find the interval to three decimals.

A random sample of 250 neighborhood homes found 35 have solar panels. With $z^{\ast }=1.96$ for a 95 percent interval for $p$, the neighborhood proportion with solar panels, compute the interval to three decimals.

Among 640 randomly selected race finishers, 384 wore tracking watches. Using $z^{\ast }=2.576$ for a 99 percent interval for $p$, the finisher proportion wearing watches, what interval results, to three decimals?

A random sample of 250 adults found 100 answered yes, so $\hat{p}=0.40$. With $z^{\ast }=1.96$ for a 95 percent interval for $p$, the adult yes proportion, which expression gives the interval?

A random sample of 160 employees found 96 want hybrid work, so $\hat{p}=0.60$. With $z^{\ast }=1.645$ for a 90 percent interval for $p$, the employee proportion wanting hybrid work, choose the expression.

A random sample of 900 residents found 270 used the bike trail, so $\hat{p}=0.30$. With $z^{\ast }=2.576$ for a 99 percent interval for $p$, the resident proportion using the trail, identify the expression.

In a random sample of 400 parents, 180 favored later school start times, so $\hat{p}=0.45$. With $z^{\ast }=1.96$ for a 95 percent interval for $p$, the parent proportion favoring later starts, which expression is correct?

A random sample of 100 college students found 64 hold a paid job, so $\hat{p}=0.64$. Using $z^{\ast }=1.96$ for a 95 percent confidence interval for $p$, what is the margin of error, to three decimals?

A random sample of 225 gym members found 81 attend classes, so $\hat{p}=0.36$. Using $z^{\ast }=1.645$ for a 90 percent confidence interval for $p$, what is the margin of error, to three decimals?

A random sample of 600 shoppers found 330 used a coupon, so $\hat{p}=0.55$. With $z^{\ast }=1.96$ for a 95 percent interval for $p$, the shopper proportion using coupons, find the margin of error to three decimals.

A random sample of 1024 library cardholders found 256 borrowed an e-book, so $\hat{p}=0.25$. Using $z^{\ast }=2.576$ for a 99 percent interval for $p$, what is the margin of error, to three decimals?