The point $\left(6,-3\right)$ lies on the curve $x^2+5y^2=81$. What is the slope of the curve there?

The point $\left(-6,5\right)$ lies on the curve $x^2-9y^2=-189$. What is the slope of the curve there?

Find $\frac{dy}{dx}$ for the relation $x+\cos y=0$.

The point $\left(-5,6\right)$ lies on the curve $x^2-2y^2=-47$. What is the slope of the curve there?

The point $\left(6,-3\right)$ lies on the curve $x^2-7y^2=-27$. What is the slope of the curve there?

Find $\frac{dy}{dx}$ for the relation $2x+\ln y=0$.

Find $\frac{dy}{dx}$ for the relation $6x^2-2y^2=-9$.

Differentiate $-3y^2$ with respect to $x$, treating $y$ as a function of $x$.

Differentiate $-3y^3$ with respect to $x$, treating $y$ as a function of $x$.

Find $\frac{dy}{dx}$ for the relation $-2x^2-2y^2=-3$.

Differentiate $-7y^2$ with respect to $x$, treating $y$ as a function of $x$.

The point $\left(-1,3\right)$ lies on the curve $x^2-7y^2=-62$. What is the slope of the curve there?

The point $\left(5,4\right)$ lies on the curve $x^2+4y^2=89$. What is the slope of the curve there?

Find $\frac{dy}{dx}$ for the relation $x^2-8y^2=-8$.

The point $\left(-4,-3\right)$ lies on the curve $x^2-5y^2=-29$. What is the slope of the curve there?

The point $\left(6,-5\right)$ lies on the curve $x^2+4y^2=136$. What is the slope of the curve there?

Find $\frac{dy}{dx}$ for the relation $5x^2-8y^2=-6$.

Find $\frac{dy}{dx}$ for the relation $-3x^2-y^2=-6$.

Find $\frac{dy}{dx}$ for the relation $-3x+\cos y=0$.

Find $\frac{dy}{dx}$ for the relation $3x^2+8y^2=4$.

Differentiate $-9y^3$ with respect to $x$, treating $y$ as a function of $x$.

Find $\frac{dy}{dx}$ for the relation $-4x+\cos y=0$.

Find $\frac{dy}{dx}$ for the relation $-6x^2-3y^2=-1$.

Find $\frac{dy}{dx}$ for the relation $-5x^2+y^2=-4$.

Find $\frac{dy}{dx}$ for the relation $-7x+\cos y=0$.

Find $\frac{dy}{dx}$ for the relation $-6x^2-5y^2=-6$.

Find an equation of the line tangent to the circle $x^2+y^2=61$ at the point $\left(-6,5\right)$, which lies on it.

Find $\frac{dy}{dx}$ for the relation $7x^2-8y^2=-1$.

Find $\frac{dy}{dx}$ for the relation $-7x+\sin y=0$.

Differentiate $2y^3$ with respect to $x$, treating $y$ as a function of $x$.

Find an equation of the line tangent to the circle $x^2+y^2=52$ at the point $\left(6,-4\right)$, which lies on it.

Differentiate $8y^2$ with respect to $x$, treating $y$ as a function of $x$.

Differentiate $-5y^3$ with respect to $x$, treating $y$ as a function of $x$.

Find $\frac{dy}{dx}$ for the relation $-3x^2+7y^2=7$.

The point $\left(-4,-5\right)$ lies on the curve $x^2-6y^2=-134$. What is the slope of the curve there?

Find an equation of the line tangent to the circle $x^2+y^2=40$ at the point $\left(2,6\right)$, which lies on it.

Find an equation of the line tangent to the circle $x^2+y^2=37$ at the point $\left(-6,-1\right)$, which lies on it.

The point $\left(2,6\right)$ lies on the curve $x^2-6y^2=-212$. What is the slope of the curve there?

Find $\frac{dy}{dx}$ for the relation $-9x^2-y^2=-2$.

Differentiate $4y^2$ with respect to $x$, treating $y$ as a function of $x$.