by BlastRoom
Checking candidate solutions against the excluded values.
#algebra_2

20 questions
One question set, multiple game modes. Tap any game to see it in action. Not sure which to pick?
Answer to place stones and capture territory.
Outrun the snow together.
Earn blasts, then hunt the other team.
Answer to earn energy, then climb.

The class blasts through walls together.
Bid on mystery lots. Most money wins.
Sell tours. Nice, standard, or a total scam.
Answer, restock, and serve the rush.
More correct answers pulls the rope your way.
Answer, then shoot down the alien wave.
Answer, then tap to leap the frozen ridge.
Clearing denominators in x/(x + 3) = -3/(x + 3) + 2 gives the candidate x = -3. Which statement about x = -3 is correct?
Clearing denominators in gives x = 8 and x = -8. Which candidate is extraneous?
Clearing denominators in gives x = 5 and x = -5. Which candidate is extraneous?
Before solving , which values of x must be excluded?
Clearing denominators in x/(x - 2) = 2/(x - 2) + 2 gives the candidate x = 2. Which statement about x = 2 is correct?
Clearing denominators in x/(x - 2) = 2/(x - 2) + 4 gives the candidate x = 2. Which statement about x = 2 is correct?
A student solves by cross multiplying, reaches 7(x - 5)(x + 4) = 0 with candidates x = 5 and x = -4, and reports both as solutions. What is the correct solution set?
Clearing denominators in gives x = 7 and x = -7. Which candidate is extraneous?
A student solves by cross multiplying, reaches 4(x - 6)(x + 5) = 0 with candidates x = 6 and x = -5, and reports both as solutions. What is the correct solution set?
Clearing denominators in gives x = 6 and x = -6. Which candidate is extraneous?
Before solving , which values of x must be excluded?
Clearing denominators in x/(x - 6) = 6/(x - 6) + 3 gives the candidate x = 6. Which statement about x = 6 is correct?
Clearing denominators in x/(x - 5) = 5/(x - 5) + 5 gives the candidate x = 5. Which statement about x = 5 is correct?
Clearing denominators in x/(x - 6) = 6/(x - 6) + 6 gives the candidate x = 6. Which statement about x = 6 is correct?
A student solves by cross multiplying, reaches 6x(x - 1) = 0 with candidates x = 0 and x = 1, and reports both as solutions. What is the correct solution set?
Before solving , which values of x must be excluded?
Clearing denominators in gives x = 3 and x = -3. Which candidate is extraneous?
Clearing denominators in gives x = 9 and x = -9. Which candidate is extraneous?
Clearing denominators in x/(x - 3) = 3/(x - 3) + 7 gives the candidate x = 3. Which statement about x = 3 is correct?
Before solving , which values of x must be excluded?
Crack the passcode before the zombies get in.
Answer, then swat bugs for bonus points.
Race through questions at your own speed.
Same question on every screen. Fastest wins.

Pick a tile, answer, hit bonuses and steals.
Graphing Rational Functions
40 questions